![combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange](https://i.stack.imgur.com/ZApvE.jpg)
combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange
![Find the term independent of x in the expansion of ( cube root x + 1/2 * cube root x - Maths - Binomial Theorem - 13125263 | Meritnation.com Find the term independent of x in the expansion of ( cube root x + 1/2 * cube root x - Maths - Binomial Theorem - 13125263 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/2315393/2012_11_06_15_11_43/mathmlequation7305014821700023745.png)
Find the term independent of x in the expansion of ( cube root x + 1/2 * cube root x - Maths - Binomial Theorem - 13125263 | Meritnation.com
The term independent of x in the expansion of (1/60 - x^8/81)(2x^2- 3/x^2)^6 is equal to : - Sarthaks eConnect | Largest Online Education Community
![Find the term independent of x in the expansion of (1+x+2x3)[(3x2/2)-(1/3x)]9 No links - Maths - Limits and Derivatives - 13477143 | Meritnation.com Find the term independent of x in the expansion of (1+x+2x3)[(3x2/2)-(1/3x)]9 No links - Maths - Limits and Derivatives - 13477143 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5c81259d40683.png)
Find the term independent of x in the expansion of (1+x+2x3)[(3x2/2)-(1/3x)]9 No links - Maths - Limits and Derivatives - 13477143 | Meritnation.com
![combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange](https://i.stack.imgur.com/6lVZt.jpg)
combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange
![Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist](https://www.tuitionwithjason.sg/wp-content/uploads/2020/05/feature-image-binomial-find-term-independent-og-x.png)